参考答案:
设电源频率为市电频率=50Hz。 (1)Z
的感抗为X
=2π
L
=2π×50×0.13=40.84Ω,
Z
=R
+jX
=6+j40.84Ω=41.28
Ω Z
的容抗为
,
Z
=R
-jX
= 15-j31.83Ω=35.19
Ω Z
与Z
串联等效复阻抗为Z=Z
+Z
=6+j40.84+15-j31.83=21+j9=22.85
Ω。设
A为参考量,则
,电路总电压U=228.5V
,负载Z
上电压U
=412.8V
,负载Z
上电压U
=351.9V (2)电路的总功率P=UIcos
=228.5×10×cos23.2°=2100W或P=I
(R
+R
)=10
×(6+15)=2100W Z
消耗的功率P
=I
R
=10
×6=600W,或P
=U
Icos
=412.8×10×cos81.6°=600W Z
消耗的功率P
=I
R
=10
×15=1500W,或P
=U
Icos
=351.9×10×cos(-64.8°)=1500W (3)电路的总无功功率Q=UIsin
=228.5×10×sin23.2°=900Var或Q=I
(X
-X
)=10
(40.84-31.83)=900Var Z
的无功功率Q
=I
X
=10
×40.84=4084Var或Q
=U
Isin
=412.8×10×sin81.6°=4084Var Z
的无功功率Q
=I
X
=10
×31.83=3183Var或Q
=U
Isin
=351.9×10×sin64.8°=3183Var (4)电路的总功率因数cos
=cos23.2°=0.919 负载Z
的功率因数cos
=cos81.6°=0.146,负载Z
的功率因数cos
=cos64.8°=0.426
相关知识:七、电气与信息